A) car is raised off the table to the top of the track. how much total work is done on the car? b) if the car is released from rest how much potential energy does the car have at the top of the track? how much kinetic energy?

Wtens = (20 N) * (5 m) * cos (0 deg) = +100 Joules

Wgrav = (20 N) * (5 m) * cos (180 deg) = -100 Joules

Wapp= (10 N) * (5 m) *cos (0 degrees) = +50 Joules

Wfrict =(10 N) * (5 m) * cos (180 degrees) = -50 Joules

Wapp = (10 N) * (5 m) * cos (0 deg) = +50 Joules

Wfrict = (10 N) * (5 m) * cos (180 deg) = -50 Joules

Explanation:

Apply the work equation to determine the amount of work done by the applied force in each of the three situations described below.

unbalanced force

explanation: