Physics, 18.01.2022 14:40 canonmille2

Can someone please help me find the answers and explain please (I will give points and thanks to whoever answers in the next 45 mins)

Can someone please help me find the answers and explain please

(I will give points and thanks to

Answers: 2

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Answer from: Quest

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.

neglecting air resistance etc etc.,

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.

vh = 8 ms-1

the vertical velocity component has an accelerating force: 'g'.

using v = u +at where a = g = 9.81 ms-2.

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.

adding vectorally gives: -

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

Answer from: Quest

the body's situation won't change the forces are equal opposit and on the same body

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

Answer from: Quest

no. bullets are macro objects. wave nature is for light waves, extremely tiny particles. if a light particle was the size of your finger, the bullet would be the size of the universe. so basically, that huge difference in size makes the wave nature of matter insignificant.

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