A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 700 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.09 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

Hi there!

We can begin by solving for the time taken for the bullet to travel a VERTICAL distance of 0.09 m due to the effects of gravity.

We can use the kinematic equation for uniform acceleration:

Since there is no initial vertical velocity:

Rearrange to solve for time. (a = g = 9.8 m/s²)

Now, we can use the distance, speed, and time equation in the horizontal direction:

Plug in the values:

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