A satellite close to the Earth (at a height of about 200 km) has an orbital speed of 8km/s. Taking the radius of the orbit as approximately equal to the Earth's radius of 6400 km, calculate the time it takes to make one orbit.

v T = 2 π R     T is time for one orbit and v the speed of the satellite

T = 2 π R / v = 2 * 3.14 * 6.4E6 / 8E3 = 5027 sec = 83.8 min

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

d. air pressure decreases as altitude increases.