A charged particle of mass 100 gm and charge +1.5 C is fixed at a position 2 m from the ground. Two charged particles of the same mass are in equilibrium 50 cm below and 60 cm above the 1st particle respectively. What is the nature and quantity of their charge?

b.

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current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

no

explanation:

no i dont know how to solve this you should probably try to google the answer