{100 POINTS + Brainliest} Driving home from school one day, you spot a ball rolling out into the street (see the figure (Figure 1)). You brake for 1.00 s , slowing your 920-kg car from 16.0 m/s to 9.50 m/s. What was the magnitude of the average force exerted on your car during braking?
What was the direction of the average force exerted on your car during braking?
How far did you travel while braking? in meters

Explanation:

According to the question ,

And we need to find out ,

As we know that Force is the rate of change of momentum ,

F = ∆p/t

F = mv - mu/t

F = m(v - u)/t

F = 920(9.5-16)/1 N

F = 920 * -6.5 N

Force = -5980N

The direction of the force will be opposite to the direction of velocity of the car .

Using the 3rd equation of motion , we have ,

2as = v² - u²

2 (v-u)/t *s =(v+u)(v-u)

2(t)(s) = v + u

2 * 1 * s = 16 + 9.5

s = 25.5/2 m

s = 12.75 m

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

i would say