Hydropower plant A has a flow of 200 kg/s and head height of 100 meters. Hydropower plant B has a flow of 100 kg/s and a head height of 200 meters. If they both have the same efficiency, which plant has the potential to produce more power

the answer is b i think

no sign of dia of fuel cell

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j