If the mass of an object is 200 kg and the applied force is 2600 N, calculate the
acceleration

a = 13 m/s²

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration  = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m  (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

i'm only doing this for the points : (

explanation:

i'm only doing this the points

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)