A 2035 kg Oldsmobile traveling east on Saginaw Street at 15.8 m/s is unable to stop on the ice covered intersection for a red light at Abbott Road. The car collides with a 4012 kg truck hauling animal feed north on Abbott at 10.5 m/s. The two vehicles remain locked together after the impact. Required:
Calculate the velocity of the wreckage immediately after the impact.

4. 50x10= 500m/s 5. 52m/s

Wooden , walls ,doors ,support

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j