Physics, 11.03.2022 01:50 leilanimontes714

300N effort is applied to lift the load of 900N by using a first class lever. If the distance between the load and fulcrum is 20m, the calculate the distance from fulcrum to the effort.

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Answer from: parbridg

Effort=300N

Load=900N

Load distance=20m

Now,

Ed=(L*Ld)/E

Ed=(900*20)/300

Ed=1800/300

Ed=6m

Explanation:

Answer from: lilquongohard

This is the correct answer!

Effort=300N

Load=900N

Load distance=20m

Now,

Ed=(L*Ld)/E

Ed=(900*20)/300

Ed=1800/300

Ed=6m

Hence, the distance from fulcrum to effort is 6 m

Explanation:

Plato

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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300N effort is applied to lift the load of 900N by using a first class lever. If the distance betwee...

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