Jupiter has a mass of 1.90*10^27 kg and a radius of 7.15*10^7 m. Assume it is a uniform solid sphere. The distance of Jupiter from the Sun is 7.79*10^11 m. (Assume Jupiter completes a single rotation in 9.93 hours and orbits the Sun once every 4.33*10^3 Earth days.) (a) What is the rotational kinetic energy of Jupiter on its axis?

(b)What is the rotational kinetic energy of Jupiter in its orbit around the Sun?

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg