If a salmon swims straight upward in the water as fast enough to break through the surface at a speed of 5 meters per second, how high can it jump about the water ?

In this problem, the formula we can use is:

v^2 = v0^2 – 2gd

where,

v = final velocity = 0 at the peak

v0 = 5 m/s

g = gravitational acceleration = 9.81 m/s^2

d = distance travelled

Calculating for d:

0 = 5^2 – 2(9.81) d

d = 1.27 m

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂