Superman lived on another planet where the acceleration due to gravity is 23.6 m/s2 . if a woman falls from a building that is 88.3 m tall, how long does he have to save her before she hits the ground?

Acceleration due to gravity = 2.6m/s²

Length of building = d = 88.3m

Time he needed before she hits the ground = ?
 we can find the time by using the formula;

D = 1/2at²

Now putting the value;

88.3 = (1/2) a t²

88.3 = 1/2 x 23.6 x t²

t² = 88.3 / 11.8

= 7.48

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft