Ariver flowing steadily at a rate of 175 m3 /s is considered for hydroelectric power generation. it is determined that a dam can be built to collect water and release it from an elevation difference of 80 m to generate power. determine how much power can be generated from this river water after the dam is filled.

137200000 watts or 137200 kilowatts The formula for power is P= dhrg Where P = Power in watts d = density of water (~1000 kg/m^3) h = height in meters r = flow rate in cubic meters per second, g = acceleration due to gravity of 9.8 m/s^2, Plugging in the known values, we get P = 1000 kg/m^3 * 80 m * 175 m^3/s * 9.8 m/s^2 P = 80000 kg/m^2 * 175 m^3/s * 9.8 m/s^2 P = 14000000 kg m/s * 9.8 m/s^2 P = 137200000 kg m^2/s^3 P = 137200000 watts or 137200 kilowatts The above figure assumes 100% efficiency which is impossible. A good efficiency would be 90% so the actual power available would be close to 0.90 * 137200 = 123480 kilowatts

The purpose of a lab is to do your "expirements" the importance of the topic is so you can now what the story is about and the last one is because no one is me with my question ( what is 3 over 4 x - 9 = 27 maybe you can )

It is the areas with lines. this may sound a little confusing, but i hope it !