Amodel rocket flies horizontally off the edge of a cliff at a velocity of 50.0 m/s. if the canyon below is 100.0 m deep, how far from the edge of the cliff does the model rocket land?

First calculate for the time it takes for the model rocket to reach the land. Using the formula:

h = vi t + 0.5 g t^2

where h is height = 100 m, vi is initial vertical velocity = 0 since it simply dropped, t is time = ?, g = 9.8 m/s^2

100 = 0.5 (9.8) t^2

t = 4.52 seconds

So the total horizontal distance taken is:

d = 50 m/s * 4.52 s

d = 225.90 m

The distance from the edge of the cliff where the model rocket will land is ; 225.90 m

Using the given data :

Velocity of rocket = 50.0 m/s

Depth of canyon ( H ) = 100 m deep

Initial velocity ( vi ) = 0

To determine how far from the edge of the cliff does the model rocket land

H = vi( t ) + 0.5gt²

100 = 0.5*(9.8)*t²

∴ t = 4.52  secs

Velocity = horizontal distance / time

∴ distance ( horizontal distance ) = velocity * time

   distance = 50 m/s * 4.52 secs = 225.90 m

Hence we can conclude that The distance from the edge of the cliff where the model rocket will land is ; 225.90 m .

Learn more : link

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.