Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. the ceiling is of height 3.6 m, and the balloons are launched at a velocity of 11 m/s. the acceleration of gravity is 9.8 m/s 2 . at what angle must they be launched to just graze the ceiling?

angle above the horizontal.

Step by Step Solution :

Given :

Launch speed = 11 m/sec

Height of the ceiling = 3.6 m

Calculation :

Let be the launch angle, measured above the horizontal.

Vertical component of initial speed is

We know that

angle above the horizontal they launched to just graze the ceiling.

For more information, refer the link given below

link

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.