Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 185 mm. neglect the weight of a and b. the coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.

By equation of equilibrium and friction:

Fb = Kx = 15(0.175) = 2.625 kN.

The wedge is on the verge of moving right then slipping will have to occur at both contact surfaces.

Fa = usNa = 0.35Na

Fb = 0.35Nb

Nb = 2.625 = 0; Nb = 2.625 kN

Nacos10 – 0.35Na sin 10 = 2.625 = 0

Na = 2.841 kN

P – (0.35 * 2.625) – 0.35 (2.841) cos 10 – 2.841 sin 10 = 0

P = 2.39 kN

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!