Aperson throws a tennis ball 6 m/s straight up. how long does it take for it to come back to their hand?

Answer

1.2245 s

Explanation

Using the Newton's law of linear motion,

v = u + gt

where v ⇒ Final velocity

            u ⇒ initial velocity,

             t ⇒ time to reach maximum height.

             g ⇒ acceleration due to gravity.

v = u + at

v = 0 m/s

g = -9.8 m/s²  (negative because the velocity is decreasing)

0 = 6 + -9.8t

9.8t = 6

t = 0.612244898 s

This is the time to reach maximum height. It will take the same time to come back to the hand.

so total time = 0.612244898 × 2

                      = 1.2245 s

ill do it for 100, also this isnt 80 its 40

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