Consider an airplane flying at a pressure altitude of 31500 ft and a density altitude of 28000 ft. calculate the outside air temperature. (round the final answer to the nearest whole number.)

1° C

Explanation:

Thinking process:

The expression for the temperature of air in terms of the density is given as follows:

T =

where is the density of air

P is the pressure of the air

R is the characteristic gas constant

pressure of air at 31500 ft  ≈ 23 800 Pa

Thus:

T =

  = 1°

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.