Where is the center of gravity if the 9.00 kg mass of the barbell itself is taken into account?

The problem is missing some parts but nevertheless here is the

Given:

1.7 m long barbell with 23 kg weight on the left and 34 in the right end.

Solution:

 Calculating from the left side:

Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34] 

Center of gravity = .992 m from the left end

! 55 !  

write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model.  

you should have at least 5 complete sentences with a main idea and supporting details.  

you must include the following words:  

potential energy

kinetic energy

mechanical energy

conservation of energy

dude, this is hard lol : ))

the answer is b i think