What is the angular speed of (a) the second hand, (b) the minute hand, and (c) the hour hand of a smoothly running analog watch? answer in radians per second?

A)We know the formula of the angular speed is                 ω = 2π / TWhere T is the time period.When second hand completes one revolution then the time taken is 60s.So T = 60sThen the angular speed of the second hand is          ω= 2π / (60s)             = 0.1047 rad/sb)When the minute hand completes one revolution the time taken is             T = 1 hr                = 3600sThen the angular speed of the minute hand is         ω =(2π) / (3600s) = 0.001745 rad/sc)When the hour hand completes one revolution then the timeperiod is          T = 12hrs             = (12)(3600)sThen the angular speed of the hour hand is         ω =(2π) / [(12)(3600)s] = 1.45444 x 10^-4 rad/s