The maximum speed of a mass m on an oscillating spring is vmax . what is the speed of the mass at the instant when the kinetic and potential energy are equal?

Let
A =  the amplitude of vibration
k =  the spring constant
m =  the mass of the object

The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω =  the circular frequency.

The velocity is
v(t) = -ωA sin(ωt)

The maximum velocity occurs when the sin function is either 1 or -1.
Therefore

Therefore


The KE (kinetic energy) is given by


The PE (potential energy) is given by


When the KE and PE are equal, then


For the oscillating spring,

Therefore


 

That would be the corect answer hope this

Iwas going to ask that quesytion  sorry dude i dont  know : (    : /