Aplayground merry-go-round has a radius of 3.0 m and a rotational inertia of 600 kg. m2. it is initially spinning at 0.80 rad/s when a 20-kg child crawls from the center to the rim. when the child reaches the rim the angular velocity of the merry-go-round is:

The solution for this problem is:

Compute first for the initial Inertia:

Initial inertia = 600 + (20 * (0 ^ 2)) = 600 kg m^2 since the radius of the child is 0 originally 

Then look for the final inertia:

Final Inertia = 600 + (20 * (3^2)) = 780 kg m^2 

Now use conservation of angular momentum:

(I final) (W final) = (I initial) (w initial) = 780w = 600(0.80)

w = (600*0.80)/780 

So, final angular velocity:

W = 0.6154 rad/s

~0.62 rad/s

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!