Mastering physics two particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation between the particles is tripled. find the new force of gravitational interaction f1.

f1 = f0/9 The gravitational force between two points is described as F = G*m1*m2/r^2 where F = Force G = Gravitational constant m1, m2 = masses r = distance between centers of masses Since everything is remaining constant except r, we can ignore their actual values and simply compare the value of 1/r^2 and 1/(3r)^2. So let's do so: 1/(3r)^2 / 1/r^2 = 1/(3r)^2 * r^2/1 = r^2/(3r)^2 = r^2/(9r^2) = 1/9 So the value of f1 will be one ninth of the value of f0, giving f1 = f0/9

Depotion can i think