Four identical 2500 kg objects are at the corners of a square with 12 m sides what is the distance between a and d

Please see attached diagram

We have square ABCD

Since ABCD is a square, all lines are of equal length

Therefore, lines AB, BC, CD and AD are 12m in length

If we draw a line from A to D, ACD forms a right angled triangle

The line AD is the hypotenuse of the right angled triangle ACD

Therefore, AC^2 + CD^2 = AD^2 (Pythagoras theorem)

AD^2 = 12^2 + 12^2

AD^2 = 144 + 144

AD^2 = 288

AD = 16.97

Therefore, the distance between A and D is 16.97m

d is the answer i came up with

explanation:

newton's third law, for every action there is an equal and opposite reaction.