What is the approximate energy of a photon having a frequency of 5 x 10^-24 hz? (h=6.6 x 10^-34 j-s)?

 To determine the frequency, we will use the equation: E = hv

Where

E is the energy of the packet

h is Planck’s constant

v is the frequency

 

since we know E and h, we have to rearrange the equation to solve for the frequency, so it would look like v = E/h

so plugging in our values:

v = E/h

= 5 x 10^-24 J / 6.626 x 10 ^-34 J/s

= 8 x 10^9 Hz

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

Answerboth technicians (a) and (b);