The solid rod shown has a radius of 0.75 in. if it is subjected to the force the 500lb determine the max normal stress developed at point

The normal stress follows the formula written below:

σ = F/A

There are two types of stress, axial and tangential. Since we are only given with the dimension of the radius (and not the length), the possible stress is axial. So, the area is,

A = πr² = π(0.75 in)² = 1.767 in²

So,
σ = F/A = 500 lb/1.767 in² = 282.94 psi