The diagram below shows two waves, wave 1 and wave 2, traveling in the same medium.

The answer is A) frequency

The amplitude of Wave 2 is greater than Wave 1's, as is the wavelength. You can see that Wave 2 has a higher period and greater peaks and troughs than Wave 1.

You can also see that Wave 2 has half the frequency, meaning Wave 1 completes 2 periods for every 1 period that Wave 2 completes. 

... The frequency of Wave-2 is half the frequency of wave-1.

... The amplitude of wave-2 is DOUBLE the amplitude of wave-1.

... The wavelength of wave-2 is DOUBLE the wavelength of wave-1.

... The wave-speeds of wave-1 and wave-2 are equal.

Go to the bathroom and vape

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.