Aflywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. the tangential acceleration of a point on its rim is:

We know that tangential acceleration is related with radius and angular acceleration according the following equation:  
at = r * aa  
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)  
So the radius is r = d/2 = 1.2/2 = 0.6 m  
Then at = 0.6 * 5 = 3 m/s2  
Tangential acceleration of a point on the flywheel rim is 3 m/s2

Ithink they do have the same properties just in less quantities i think