Physics, 01.08.2019 07:30 meiyrarodriguez

Achild, starting from rest at the top of a playground slide, reaches a speed of 7.0 meters per second at the bottom of the slide. what is the vertical height of the slide? [neglect friction.]

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We know that the child will follow a accelerated movement due the gravity, according these equations:
h = v0 * t + 1/2 * g * t^2
v = v0 + g*t
where h is height, v is final speed, v0 is initial speed, g is gravity constant equal to 9.8 m/s2 and t is time
So the time to reach the bottom of the slide
v = v0 + g*t => 7 = 0 + 9.8*t
t = 7/9.8 = 0.714 seconds
And then the height is:
h = v0*t + 1/2*g*t^2
h = 0*0.714 + 1/2*9.8*0.714^2 = 2.5 meters
So the height of the slide is 2.5 meters

Answer from: suselygonza

The vertical height achieved by child during sliding is 2.50 m

Given data:

The initial speed of child is, u = 0 m/s. (Since child was initially at rest)

The final speed of child is, v = 7 m/s.

Apply first kinematic equation of motion to obtain the value of time (t) to achieve the vertical height (h) as,

v=u+gt

Here, g is the gravitational acceleration.

Solving as,

$7.0=0+(9.8)t\\t=0.714 \;\rm s$

Now, apply the second kinematic equation of motion as,

$h=ut+\dfrac{1}{2}gt^{2}\\\\h=(0 \times t) +\dfrac{1}{2} \times 9.8 \times 0.714^{2}\\h \approx 2.50 \;\rm m$

Thus, we can conclude that the vertical height of the slide is 2.50 m.

Learn more about kinematic equations of motion here:

link

Answer from: Quest

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015

Answer from: Quest

You need to be more specific. i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time, then constant velocity is a straight line . . i.e. a line that has constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant velocity is a piece of line that lies on the x-axis . . it's value is zero.

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