A300kg motorboat is turned off as it approaches a dock and coasts towards it at .5 m/s. isaac, whose mass is 62 kg jumps off the front of the boat with a speed of 3m/s relative to the boat. what is the velocity of the boat after isaac jumps?

Momentum is conserved
momentum = mass×velocity
momentum before docking = 300×0.5=150
momentum after isaac jumps = 150, mass of boat after he jumps = 300-62=238 kg
150= (62×3)+(238×velocity)
velocity = 0.151 m/s in the opposite direction to the movement of isaac