An archer shoots an arrow toward a 300-g target that is sliding in her direction at a speed of 2.40 m/s on a smooth, slippery surface. the 22.5-g arrow is shot with a speed of 38.5 m/s and passes through the target, which is stopped by the impact. what is the speed of the arrow after passing through the target?

The speed of the arrow after passing through the target is 6.5 m/s

Explanation:

Given that,

Mass of target = 300 g

Speed of target = 2.40 m/s

Mass of arrow = 22.5 g

Speed of arrow = 38.5 m/s

After impact the momentum of the target is zero since its velocity is zero.

After impact the velocity of the arrow can be determined with conservation of momentum

We need to calculate the speed of the arrow after passing through the target

Using conservation of momentum

Put the value into the formula

Hence,The speed of the arrow after passing through the target is 6.5 m/s

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.