A500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

= air resistance force - force of parachutist

= 800-500

= 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

pe = weightxheight = 2000x1000=2,000,000joules