Apiston in a gasoline engine is in simple harmonic motion. the engine is running at the rate of 3 540 rev/min. taking the extremes of its position relative to its center point as ±4.50 cm. (a) find the magnitude of the maximum velocity of the piston. correct: your answer is correct. m/s (b) find the magnitude of the maximum acceleration of the piston km/s2

A)The rpm is 3540 rev/ min
1 rev = 2πr, where r is the radius,
Therefore, the velocity
         =3540 ×2π ×4.5/100 
         = (1001.04)/60
         = 16.684 m/s

b)  ω = 2πf , where ω is the angular velocity and f is the frequency (oscillations) per second
=2π (3540/60) 
= 2π (59)
= 370.756 rad/sec
a(max) = (370.756)² × 0.045 
            =  6185.70 m/s²
            = 6.186 km/s²

The answer is b hope this