Physics, 02.08.2019 03:30 Sruyle51230

9) what would be the weight of a 59.1-kg astronaut on a planet with the same density as earth and having twice earth's radius?

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Answer from: cocoapop

The weight of the astronaut is given by
W=mg

where m=59.1 kg is his mass and g=9.81~m/s^2

is the gravitational acceleration on Earth.

To solve the problem, we must find the value of g on the new planet. g is given by
$g= \frac{GM}{r^2}$
where G is the gravitational constant, M the mass of the planet and r its radius.
The mass of the planet can be written as
M=dV

where d is the density and V the volume.
We can assume that the planet is a sphere, therefore the volume is proportional to r^3

:
$V= \frac{4}{3}\pi r^3$
and we can write the mass as
$M= \frac{4}{3} \pi d r^3$
and then, g becomes
$g= \frac{GM}{r^2}= \frac{4}{3} \frac{G \pi d r^3}{r^2}= \frac{4}{3} G \pi d r$
So, in the end g is proportional to the radius of the planet, r (because the density of the new planet d is the same as the Earth's one. If the radius of the new planet is twice the Earth's radius, g will be twice the value of g on Earth:
$g_{new}=2g=2\cdot9.81~m/s^2=19.62~m/s^2$
And since the mass of the astronaut is always the same, the weight on the new planet will be twice the weight on Earth:
$W_{new}=mg_{new}=2mg=1159~N$

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

slope of a graph = change in value of y -axis / change in values of x -axis

comparing both the equations

change in value of y -axis = change in position

change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

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