Physics, 01.08.2019 21:00 yoridff

The ocean is a store house of carbon which is absorbed in the form of carbon dioxide from the air. the carbon dioxide dissolved in ocean waters is used by marine plants to make food by the process of photosynthesis. the paragraph most likely describes the interactions of the ocean with the geosphere and biosphere, b cryosphere and biosphere c atmosphere and cryosphere d biosphere and atmosphere

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Answer from: xojade

The paragraph doubtlessly depicts the associations of the sea with the biosphere and atmosphere. Once in the oceans, the CO2 never again traps warm. CO2 additionally moves immediately between the atmosphere and the land biosphere. Atmosphere, oceans, and land biosphere where carbon is put away, around 93 percent of the CO2 is found in the oceans.

Answer from: cassiuspricerules

The correct answer is option D, biosphere and atmosphere

Explanation:

Biosphere is that part of earth which includes all the livings things even though if they lies in the deepest ocean. Now these components of biosphere are using the carbon dioxide which has been derived from the atmosphere of the earth. Exchange of product, or processes between the two spheres of earth is known as interaction between the spheres. Thus in the given question, there exists an interaction between the atmosphere and the biosphere of earth.

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

Answer from: Quest

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way

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