Auniform rod xy of weight 10.0n is freely hinged to a wall at x. it is held horizontal by a force f acting from y at an angle 30° to the horizontal, as shown. what is the value of f? a- 5.0 n b- 8.7cm c- 10.0cm d-20.0cm

The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:

Given data:

The weight of rod is, W = 10.0 N.

The angle made by force with respect to horizontal is, .

To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.

Therefore,

Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.

Learn more about the equilibrium of forces here:

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probably not if net force is zero

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.