Devonte pushes a wheelbarrow with 830 w of power. how much work is required to get the wheelbarrow across the yard in 11 s? round your answer to two significant figures.

To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Explanation:

Hi, to solve this problem we have to apply the formula:

Power (w) = work (J) / time (sec)

So, replacing the variables with the values given:

830 w = work / 11sec

Isolating work we have:

830 w / 11 sec = work

Work = 9,130 J  = 9,100 j (rounded to two significant figures)

To get the wheelbarrow across the yard in 11 s Is required 9,100 J of work.

Feel free to ask for more if it´s necessary or if you did not understand something.

9100

Explanation:

EDGE2020

need to see circuit to get time constant

grav potential energy