Asprinkler sprays water out of a hose with a velocity of 6.3 m/s. if the sprinkler is aimed 25â° above the ground, at what distance from the sprinkler does the water hit the ground? ignore air resistance and use 9.8 m/s2 for acceleration due to gravity.

The step by step solution would be:

1. Look for the vertical component of spray, this is calculated by: (sin 25 degrees x 6.3) =2.662 m/sec. 

2. Then look for the time to max height = (v/g) = 2.662/9.8 = 0.272 sec. 

3. Double the amount you got from 2; this is for time to reach the ground, = 0.544 sec. 

4. Then compute for the horizontal V of spray = (cos 25 degrees x 6.3) = 5.710 m/sec. 

5. So the horizontal distance = (5.710 x 0.544) = 3.106 meters.