When light from one source, x, strikes a metal, electrons are ejected. when light from another source, y, strikes the same metal, electrons are not ejected. which best explains why this occurs? light from source x has a higher intensity than light from source y. light from source x has a lower intensity than light from source y. photons of light from source x carry more energy than photons of light from source y. photons of light from source x carry less energy than photons of light from source y.

Photons of light from source X carry more energy than photons of light from source Y

Explanation: This is based on the fact that light is a electromagnetic radiation. When a photon hits an electron on a metal surface, the electron can be emitted. The emitted electrons are called photoelectrons.

E= energy

h= Planck's constant

= frequency of incident radiation

= threshold frequency

In order to eject an electron, the incident radiation must possess frequency greater than threshold frequency and a light with higher frequency has higher energy. Thus higher energy radiation can easily eject electrons.

Thus we can conclude Photons of light from source X carry more energy than photons of light from source Y

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