Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

The capacitance of each capacitor is .

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

It can be given as,

Here, is the charge and is the voltage.

Given information-

The voltage of the battery is 5.55 V.

The value of charge is C.

Put the values in the above formula as,

Given that the three uncharged capacitors with equal capacitance are combined in parallel.

For the parallel connection of the capacitance the equivalent capacitance can be given as,

Here, is the capacitance of each capacitors. Put the values,

Hence the capacitance of each capacitor is .

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u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg