Physics, 30.07.2019 02:30 kaykayhodge

During each heartbeat, about 80 g of blood is pumped into the aorta in approximately 0.2 s. during this time, the blood is accelerated from rest to about 1 m/s. what is the average force on the blood during this time?

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Answer from: mihir50

The average force acting on the blood as it is pumped into the aorta is $\boxed{0.4\text{ N}}$ .

Explanation:

As the blood enters the aorta, the speed of the blood increases from zero to $1\text{ m/s}$ in a time of $0.2\text{ s}$ . It means that the blood moves under the acceleration as it passes through the aorta.

The acceleration produced in a body is due to the force experienced by the particular amount of blood as it enters the aorta.

Write the expression for the acceleration of the blood as its speed increases.

$\boxed{a=\dfrac{v_{f}-v_{i}}{t}}$ ...... (1)

Here, $v_{f}$ is the final velocity of blood, $v_{i}$ is the initial velocity and is the time taken to accelerate.

Substitute the values of the velocities and the time taken by the blood in equation (1).

$a&=\dfrac{1-0}{0.2}\text{ m}\text{/s}^2}\\&=\dfrac{1}{0.2}\text{ m}\text{/s}^2}\\&=5\text{ m}\text{/s}^2}$

The net force acting on the blood is given by:

$F=m\times{a}$ ...... (2)

Substitute the values of mass and acceleration in the above expression.

$\begin{aligned}F&=80\text{ g}\left(\dfrac{1 \text{ kg}}{1000\text{ g}}\right)\times\left(5\text{ m/s}^2\right)\\&=0.08\times5\text{ N}\\&=0.4\text{ N}\end{aligned}$

Therefore, the average force acting on the blood as it is pumped into the aorta is $\boxed{0.4\text{ N}}$ .

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Force and acceleration

Keywords:

heartbeat, average force, aorta, blood, rest, speed up, acceleration, initial speed, final speed, time, accelerated, 80 g, blood is pumped.

Answer from: Quest

Electoral current force mechanical advantage if the wheel and axle is 2 n and the output force is 20 n

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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During each heartbeat, about 80 g of blood is pumped into the aorta in approximately 0.2 s. during t...

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