The force in newtons on a particle directed along the x-axis is given by f(x)=exp(−(x/2)+6) for x≥0 where x is in meters. the particle is constrained to move along the x-axis. find the work done in joules on the particle, w, in moving it from x=0 to x=1 using the fact that f=dw/dx. for your reference, 1 joule = 1 newton × 1 meter.,