Scientists want to place a 3700 kg satellite in orbit around mars. they plan to have the satellite orbit a distance equal to 1.9 times the radius of mars above the surface of the planet. here is some information that will solve this problem: mmars = 6.4191 x 1023 kg rmars = 3.397 x 106 m g = 6.67428 x 10-11 n-m2/kg2 1) what is the force of attraction between mars and the satellite?

The force of attraction between Mars and the satellite is:

where G is the gravitational constant, M the mass of Mars, m the mass of the satellite, and d the distance of the satellite from the center of Mars.

First we have to calculate d. Calling r the radius of Mars, we know that the satellite is located at 1.9r above the surface. This means that its distance from the center of Mars is .
Using this information, and the data given by the problem, we can now calculate the intensity of the gravitational attraction:

The rocks expand when there hot/warm  and contract when they are cold.