If you put in 10 j of work to push 1 c of charge against and electric field what will be its voltage with respect to its starting position? when released, what will be it’s kinetic energy if it flies past it’s starting position?

It will have a value if 10V as a volt is a measurement of joules per charge so if there is 10j and 1c that makes 10V and since there is 10 J at its position using .5mv^2 we can solve this. First we find mass by knowing per electron it has a mass of 9.1E-31 kg and a charge is 1.6E-19C so we then divide 1C/1.6E-19 getting us roughly 6.2E18 electrons, then by multiplying the number of electrons by mass of an electron we get the total mass which is 5.642E-12kg. Now we can use the energy equation and plug in out mass so 10J=.5*(5.642E-12kg)*v^2. Then isolating v we end up with sqrt (2(10J)/5.642E-12kg)=V so V equals 3.5E12

This is kenetic energy.