Hlppp you. o two students are doing an experiment. they mix 40 grams of baking soda with 23 grams of vinegar inside a closed container and watch it react. how many grams of product should they expect to have when the reaction stops?

mass of product= 40 +23= 63 grams

Explanation:

we use the law of conservation of mass which says that mass can neither be created and nor destroyed.So sum of mass of all the reactants is equal to the sum of mass of all the products.

Here sum of mass of reactants= 40+23= 63 grams

so the mass of products=63 grams

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂