A78.1 kg ice skater is moving at 2.93 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. she then moves in a circle of radius 0.556 m around the pole. find the force exerted by the rope on her arms. the acceleration of gravity is 9.8 m/s 2 . answer in units of kn.

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s