Abaseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?

The work done by the friction force to stop the player is equal to his loss of kinetic energy:


The work done by the friction force is the magnitude of the force  times the distance covered by the player, d:


The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):


Substituting into the first equation, we get:

from which we find d, the distance covered by the player:

Divide 108.2 x 10^6 into 1.5 x 10 and the result will be in au (astronomical units)