What is the magnetic force on a proton that is moving at 4.5 x 10^7 m/s to the right through a magnetic field that is 1.6 t and pointing away from you? the charge on a proton is 1.6 x 10^-19 c. a. 1.2 x 10^-19 n down b. 1.2 x 10^-11 n up c. 7.2x 10^-7 n up d. 7.2 x 10^-7 n down

The magnetic force on a charged particle is given as: F = qvBsinФ
B is the magnetic field.
q is the charge on the particle.
v is the velocity of the charged particle.
 Ф is the angle between magnetic field (B) & the velocity of charge (v).

⇒ F = qvb sin Ф

Here, Ф = 90 degree.
and sin 90 = 1
Putting the values in the equation, we get,

F = 1.6 x 10^-19 C × 4.5 × 10^7 m/s × 1.6 T
= 11.52 × 10^-12N
= 1.2 x 10^-11 N up

It's because 3 if it was 10 it wouldn't look right do it goes up to 4d

Sorry i don’t know what to do