Physics, 18.01.2020 15:31 Lalagrl

1.how does inertia affect a person who is not wearing a seatbelt during a collision?
2.how does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at 60 mph?
3.how does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle?
4.keeping in mind the kinetic energy of a moving vehicle, how can a driver best prepare to enter sharp curves in the roadway?
5.using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuries.

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Inertia is the tendency of an object to stay in motion when it is in motion. This is basically Newton's first law. The person in the car is still in motion when the car crashes and If there's no seatbelt to increase the time of the crash then there will be a larger force. 2. A car traveling at a higher rate of speed will have more kinetic energy than if it were to be traveling at a lower speed. The formula for kinetic energy is (1/2)* mass* velocity^2. Therefore doubling the velocity will affect it by a factor of 4. (4x greater). 3. A driver can slow down before entering the curve as a smaller tangent velocity will affect the centripetal force less. 4. Force= mass* acceleration so if a car has a higher acceleration then there will be a greater force of impact. And this also goes back to question 1 with the seatbelts.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

The next element is345640

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